8s^2+2s-6=0

Solution for 8s^2+2s-6=0 equation:

8s^2+2s-6=0

a = 8; b = 2; c = -6;
Δ = b2-4ac
Δ = 22-4·8·(-6)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*8}=\frac{-16}{16}
=-1
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*8}=\frac{12}{16}
=3/4
$